04 · General Ability — Q91–120 — KIPS Mock Tests — CSS MPT 2026

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Study order: attempt the question → open the yellow hint only if needed → reveal the green answer → try the related question. Check the revision box only when you can explain the rule without looking.

30 original questions + 30 related recall exercises. Study solutions, not an official KIPS key. Wording and options are retained with spacing and obvious numbering normalised. Consult the attached original PDF for exact typography.

Q91

4, 6, 12, 14, 28, 30, ___?

a) 32

b) 64

c) 62

d) 60

Source PDF page 9.

💡 Hint — try before revealing

Test alternating operations rather than one repeated difference.
✅ Answer & explanation

Answer: D — 60

Reasoning: Alternate +2 and ×2: 4→6→12→14→28→30→60.

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Related practice: What follows 60 under the same rule?

✅ Related answer & memory link

Answer: 62.

Why / remember: After the ×2 step, the next operation is +2; 60 therefore becomes 62.
Confident after revision

Q92

, 120, 40, 10, 2.

a) 480

b) 240

c) 220

d) 120

Source PDF page 9.

💡 Hint — try before revealing

Inspect the successive divisors between neighbouring terms.
✅ Answer & explanation

Answer: B — 240

Reasoning: Divide successively by 2, 3, 4 and 5: 240→120→40→10→2.

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Related practice: What follows 2 if the pattern continues?

✅ Related answer & memory link

Answer: 1/3, after division by 6.

Why / remember: The divisors increase 2,3,4,5, so the next is 6: 2÷6=1/3.
Confident after revision

Q93

In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number

of votes was 7500, the number of valid votes that the other candidate got?

a) 2700

b) 2900

c) 3000

d) 3100

Source PDF page 9.

💡 Hint — try before revealing

Find valid votes first, then the other candidate’s share of that smaller total.
✅ Answer & explanation

Answer: A — 2700

Reasoning: Valid votes = 7500×0.8=6000. The other candidate gets 45%: 6000×0.45=2700.

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Related practice: How many votes were invalid?

✅ Related answer & memory link

Answer: 1500.

Why / remember: Invalid votes are 20% of all 7500 votes: 0.20×7500=1500.
Confident after revision

Q94

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the

sum of their marks. The marks obtained by them are?

a) 39, 30

b) 41, 32

c) 42, 33

d) 43, 34

Source PDF page 9.

💡 Hint — try before revealing

The difference between the percentage shares corresponds to nine marks.
✅ Answer & explanation

Answer: C — 42 and 33

Reasoning: The difference is 56%−44%=12% of the total. Total=9/0.12=75; shares are 42 and 33.

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Related practice: What percentage did the lower scorer obtain of their combined marks?

✅ Related answer & memory link

Answer: 44%.

Why / remember: With only two shares, the lower percentage is 100−56=44%.
Confident after revision

Q95

The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year

is:

a) 4.37%

b) 5%

c) 6%

d) 8.75%

Source PDF page 9.

💡 Hint — try before revealing

Separate a simple annual average from a compounded annual rate.
✅ Answer & explanation

Answer: B — 5%, simple annual average

Reasoning: Total growth=(262500−175000)/175000=50%; divide by 10 for 5%. Compound annual growth is about 4.14%, not 5%.

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Related practice: What formula gives compound annual growth?

✅ Related answer & memory link

Answer: [(Final/Initial)^(1/years)−1]×100.

Why / remember: Compounding asks what repeated annual multiplier produces the full final-to-initial ratio; take the nth root.
Confident after revision

Q96

19 % of 900?

a) 100

b) 20

c) 81

d) None of these

Source PDF page 9.

💡 Hint — try before revealing

Convert a percentage to a decimal before multiplying.
✅ Answer & explanation

Answer: D — None; 171

Reasoning: 19%×900=0.19×900=171.

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Related practice: What is 21% of 900?

✅ Related answer & memory link

Answer: 189.

Why / remember: 21% of 900 is 0.21×900=189; 1% is 9, so 21 lots give the same result.
Confident after revision

Q97

What percent is 70 of 280?

a) 25%

b) 50%

c) 75%

d) None of these

Source PDF page 9.

💡 Hint — try before revealing

Use part ÷ whole ×100, keeping the denominator in the correct position.
✅ Answer & explanation

Answer: A — 25%

Reasoning: 70/280×100=25%. Divide part by whole before multiplying by 100.

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Related practice: What fraction equals 25%?

✅ Related answer & memory link

Answer: 1/4.

Why / remember: 25/100 reduces to 1/4; percentages and fractions are alternate forms of the same proportion.
Confident after revision

Q98

The ratio of the number of boys and girls in a college is 7: 8. If the percentage increases in the number of boys and girls by

20% and 10% respectively, what will be the new ratio?

a) 8:9

b) 17:18

c) 21:22

d) Cannot be determined

Source PDF page 10.

💡 Hint — try before revealing

Apply each increase to its own original ratio part.
✅ Answer & explanation

Answer: C — 21:22

Reasoning: New ratio=7×1.20 : 8×1.10=8.4:8.8=21:22.

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Related practice: What happens if both groups grow by the same percentage?

✅ Related answer & memory link

Answer: Their ratio stays unchanged.

Why / remember: Equal percentage changes multiply both parts by the same factor, which cancels in a ratio.
Confident after revision

Q99

Salaries of Rizwan and Salman are in the ratio 2:3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40:57.

What is Salman salary?

a) Rs. 17,000

b) Rs. 20,000

c) Rs. 25, 000

d) Rs. 34, 000

Source PDF page 10.

💡 Hint — try before revealing

Write an equation using the new ratio, but check whether the question asks for the old salary.
✅ Answer & explanation

Answer: D — Rs 34,000, original salary

Reasoning: Let salaries be 2x and 3x. 57(2x+4000)=40(3x+4000), so x=11333⅓ and Salman’s original salary=34000.

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Related practice: What is Salman’s salary after the increase?

✅ Related answer & memory link

Answer: Rs 38,000.

Why / remember: The original Rs 34,000 plus Rs 4,000 gives Rs 38,000; the two answers belong to different time points.
Confident after revision

Q100

Point X is in North of point Y and point Y is in east of point Z. To which direction is point X w.r.t. Z?

a) North-east

b) North-west

c) East

d) None of these

Source PDF page 10.

💡 Hint — try before revealing

Draw east and north displacements from the reference point.
✅ Answer & explanation

Answer: A — North-east

Reasoning: From Z go east to Y, then north to X; the displacement has east and north components.

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Related practice: What direction is Z from X?

✅ Related answer & memory link

Answer: South-west.

Why / remember: Reversing the direction reverses both components: north-east becomes south-west.
Confident after revision

Q101

Point A is located 8km south of B and C is located 6km west of A. What is the distance between C and B?

a) 8km

b) 12km

c) 10km

d) 9km

Source PDF page 10.

💡 Hint — try before revealing

The two perpendicular legs require the Pythagorean theorem.
✅ Answer & explanation

Answer: C — 10 km

Reasoning: The perpendicular legs are 8 and 6 km: √(64+36)=10.

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Related practice: What familiar right-triangle ratio is this?

✅ Related answer & memory link

Answer: 3:4:5 scaled by 2.

Why / remember: 6:8:10 reduces to 3:4:5, a useful right-triangle triple.
Confident after revision

Q102

A is the father of B, but B is not the son of A. what is B to A?

a) Daughter

b) Father

c) Mother

d) None of these

Source PDF page 10.

💡 Hint — try before revealing

Identify the stated parent before deciding the child’s relationship.
✅ Answer & explanation

Answer: A — Daughter

Reasoning: Under the usual binary family-relation convention, a child who is not a son is a daughter.

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Related practice: If B is A’s daughter, A is B’s what?

✅ Related answer & memory link

Answer: Father, as stated in the question.

Why / remember: The question explicitly supplies that A is the father; the answer does not come from the letters themselves.
Confident after revision

Q103

The old man’s son is my son’s uncle. What is the old man to me?

a) Brother

b) Father

c) Uncle

d) None of these

Source PDF page 10.

💡 Hint — try before revealing

Ask whether the uncle could belong to either parent’s family.
⚠️ Answer & question issue

Answer: B — Father, intended; not unique

Reasoning: If the old man’s son is my brother, the old man is my father. The uncle could instead be related through my spouse, so father-in-law is also possible.

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Related practice: What extra fact makes father certain?

✅ Related answer & memory link

Answer: That the uncle is my own brother.

Why / remember: Stating that the uncle is my own brother removes the spouse-side possibility and fixes the older man as my father.
Confident after revision

Q104

Two dice are thrown simultaneously. What is the probability of getting two numbers, whose product is even?

a) 1/2

b) 3/4

c) 3/8

d) 5/16

Source PDF page 10.

💡 Hint — try before revealing

It is easier to calculate the complement: when is a product odd?
✅ Answer & explanation

Answer: B — 3/4

Reasoning: A product is odd only if both dice show odd numbers: (3/6)²=1/4. Complement=3/4.

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Related practice: What is the probability both dice are odd?

✅ Related answer & memory link

Answer: 1/4.

Why / remember: Each die has three odd faces out of six, so independent probabilities multiply: 1/2×1/2=1/4.
Confident after revision

Q105

The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20

years. The present age of the husband is:

a) 35 years

b) 40 years

c) 50 years

d) None of these

Source PDF page 10.

💡 Hint — try before revealing

Convert averages into totals and add the years gained by every person.
✅ Answer & explanation

Answer: B — 40 years

Reasoning: Family total now=3×27+9=90. Wife+child now=2×20+10=50. Husband=40.

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Related practice: Why add 9 to the first total?

✅ Related answer & memory link

Answer: Three people each age three years.

Why / remember: A three-person family gains 3×3=9 total age-years in three years, not just three.
Confident after revision

Q106

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red

nor green?

a) 1/3

b) 3/4

c) 7/19

d) 9/21

Source PDF page 10.

💡 Hint — try before revealing

Neither of two colours means the remaining colour; count all balls in the denominator.
✅ Answer & explanation

Answer: A — 1/3

Reasoning: Neither red nor green means blue. There are 7 blue among 21 balls: 7/21=1/3.

🔁

Related practice: Probability of red?

✅ Related answer & memory link

Answer: 8/21.

Why / remember: Red probability is 8/(8+6+7)=8/21, assuming one uniformly random draw.
Confident after revision

Q107

Naeem sold a computer for Rs 25000 at which he suffered 20 Percent loss. Find the purchase price of the computer?

a) 31000

b) 41250

c) 31250

d) None of these

Source PDF page 10.

💡 Hint — try before revealing

A 20% loss means selling price is 80% of cost price.
✅ Answer & explanation

Answer: C — Rs 31,250

Reasoning: Selling price is 80% of cost. Cost=25000/0.8=31250.

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Related practice: What would a 20% profit selling price be?

✅ Related answer & memory link

Answer: Rs 37,500.

Why / remember: After finding cost Rs 31,250, multiply by 1.20 for a 20% profit: Rs 37,500.
Confident after revision

Q108

Two sides of a right triangle are 12 & 13. Which of the following could be the length of third side?

a) 5

b) √31

c) 11

d) √313

Source PDF page 10.

💡 Hint — try before revealing

Check whether the stated sides must be legs or whether one may be the hypotenuse.
⚠️ Answer & question issue

Answer: A and D — 5 or √313

Reasoning: If 13 is the hypotenuse, third side=√(169−144)=5. If 12 and 13 are legs, hypotenuse=√313. Two listed options work.

🔁

Related practice: What extra condition selects 5 uniquely?

✅ Related answer & memory link

Answer: State that 13 is the hypotenuse.

Why / remember: If 13 is explicitly the hypotenuse, the remaining leg is √(13²−12²)=5; otherwise another arrangement is possible.
Confident after revision

Q109

If A+B=2C and C+D=2A, then:

a) A+C=B+D

b) A+C=2D

c) A+D=B+C

d) A+C=2B

Source PDF page 10.

💡 Hint — try before revealing

Translate each twice relationship into an equation before adding.
✅ Answer & explanation

Answer: A — A+C=B+D

Reasoning: B=2C−A and D=2A−C; adding gives B+D=A+C.

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Related practice: If A=3 and C=4, what are B and D?

✅ Related answer & memory link

Answer: B=5 and D=2.

Why / remember: With A=3 and C=4, B=2C−A=5 and D=2A−C=2; both sides of A+C=B+D equal 7.
Confident after revision

Q110

Find out the two signs to be interchanged for making following equation correct: 5+3x8-12/4=3

a) + and –

b) - and ÷

c) + and ×

d) + and ÷

Source PDF page 11.

💡 Hint — try before revealing

After swapping the signs, apply normal operator precedence.
✅ Answer & explanation

Answer: B — minus and division

Reasoning: After exchange: 5+3×8÷12−4=5+2−4=3. Apply multiplication/division before addition/subtraction.

🔁

Related practice: What is 18÷3×2?

✅ Related answer & memory link

Answer: 12; evaluate equal-precedence operations left to right.

Why / remember: Multiplication and division have equal precedence, so 18÷3×2 is evaluated left to right: 6×2=12.
Confident after revision

Q111

A sum of Rs.312 was divided among 100 boys and girls in such a way that the boy gets Rs.3.60 and each girl gets Rs.2.40,

then the number of girls is:

a) 35

b) 40

c) 45

d) 50

Source PDF page 11.

💡 Hint — try before revealing

Compare the actual payment with an all-boys baseline.
✅ Answer & explanation

Answer: B — 40 girls

Reasoning: If everyone received Rs 3.60, total=360. Each girl lowers it by 1.20; girls=(360−312)/1.20=40.

🔁

Related practice: How many boys are there?

✅ Related answer & memory link

Answer: 60.

Why / remember: The total is 100 children; subtract 40 girls to obtain 60 boys.
Confident after revision

Q112

If the price of a book is first decreased by 25% and then increased by 20%, then the net change in the price will be?

a) 10

b) 20

c) 30

d) 40

Source PDF page 11.

💡 Hint — try before revealing

Multiply successive price factors; do not simply subtract the percentages.
✅ Answer & explanation

Answer: A — 10% decrease

Reasoning: Price factor=0.75×1.20=0.90. The printed options omit the percent sign and direction.

🔁

Related practice: What increase reverses a 25% decrease?

✅ Related answer & memory link

Answer: 33⅓%.

Why / remember: After a 25% fall, the base is 75. Restoring 25 requires 25/75=33⅓% growth.
Confident after revision

Q113

A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are:

a) 500

b) 600

c) 800

d) 1000

Source PDF page 11.

💡 Hint — try before revealing

The passing score is obtained marks plus the shortfall.
✅ Answer & explanation

Answer: A — 500

Reasoning: Pass marks=125+40=165=33% of total. Total=165/0.33=500.

🔁

Related practice: What are 40% of the total marks?

✅ Related answer & memory link

Answer: 200.

Why / remember: Once the total is 500, 40% equals 0.40×500=200.
Confident after revision

Q114

If a dice is rolled twice then what is the probability that the sum of the number of dots shown is 8?

a) 5/36

b) 4/36

c) 1/12

d) 1/2

Source PDF page 11.

💡 Hint — try before revealing

List ordered dice pairs: (2,6) differs from (6,2).
✅ Answer & explanation

Answer: A — 5/36

Reasoning: Sum 8 comes from (2,6),(3,5),(4,4),(5,3),(6,2): five of 36 ordered outcomes.

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Related practice: Which sum has six ordered outcomes?

✅ Related answer & memory link

Answer: 7.

Why / remember: Sum seven has six ordered outcomes, from (1,6) through (6,1), among 36 equally likely pairs.
Confident after revision

Q115

A library has an average of 510 visitors on Sunday and 240 on other days. The average number of visitors per day in a month

of 30 days beginning with a Sunday is:

a) 285

b) 290

c) 297

d) 305

Source PDF page 11.

💡 Hint — try before revealing

Weight each daily average by how many days of that type occur.
✅ Answer & explanation

Answer: A — 285

Reasoning: A 30-day month starting Sunday has five Sundays and 25 other days. Average=(5×510+25×240)/30=285.

🔁

Related practice: Why not average 510 and 240 directly?

✅ Related answer & memory link

Answer: The two daily categories occur unequal numbers of times.

Why / remember: A simple mean of the two attendance figures wrongly gives both types equal weight even though there are five versus twenty-five days.
Confident after revision

Q116

A pupil’s marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half.

The number of pupils in the class is:

a) 45

b) 40

c) 39

d) 37

Source PDF page 11.

💡 Hint — try before revealing

A change in total equals number of students times change in mean.
✅ Answer & explanation

Answer: B — 40, if “half” means 0.5 mark

Reasoning: The erroneous total rose by 20. Class size=20/0.5=40. The paper should specify half a mark.

🔁

Related practice: If the average rose by 0.4 mark instead, what is the class size?

✅ Related answer & memory link

Answer: 50.

Why / remember: If the total error is 20 marks and the mean changes by 0.4, class size is 20/0.4=50.
Confident after revision

Q117

The average weight of 8 persons increases by 2.5kg when a new person comes in place of one of them weighing 65kg. What

might be the weight of the new person?

a) 70kg

b) 75kg

c) 80kg

d) 85kg

Source PDF page 11.

💡 Hint — try before revealing

Replacing one person changes the group total by group size times the mean change.
✅ Answer & explanation

Answer: D — 85 kg

Reasoning: Total weight rises by 8×2.5=20 kg. New person=65+20=85.

🔁

Related practice: If the mean fell by 2 kg, what would the replacement weigh?

✅ Related answer & memory link

Answer: 49 kg.

Why / remember: A fall of 2 kg for eight people is a total fall of 16 kg; replacement weight=65−16=49.
Confident after revision

Q118

The average of 7 consecutive numbers is 20. The largest of these numbers is:

a) 21

b) 22

c) 23

d) 24

Source PDF page 11.

💡 Hint — try before revealing

For an odd number of consecutive integers, the average is the middle term.
✅ Answer & explanation

Answer: C — 23

Reasoning: Seven consecutive integers centre on 20: 17,18,19,20,21,22,23.

🔁

Related practice: What is their sum?

✅ Related answer & memory link

Answer: 140.

Why / remember: Sum equals count×mean: 7×20=140.
Confident after revision

Q119

If FRIEND is coded as HUMJTK, how is CANDLE written in that code?

a) EDRIRL

b) DCQHQK

c) ESJFME

d) DEQJQM

Source PDF page 11.

💡 Hint — try before revealing

Compare each letter’s alphabet position with the corresponding coded letter.
✅ Answer & explanation

Answer: A — EDRIRL

Reasoning: Add 2,3,4,5,6,7 alphabet positions successively to C,A,N,D,L,E.

🔁

Related practice: Which shift is applied to the sixth letter?

✅ Related answer & memory link

Answer: +7.

Why / remember: The successive shifts start at +2 and increase by one, so the sixth shift is +7.
Confident after revision

Q120

If ROSE is coded as 6821, CHAIR is coded as 73456 and PREACH is coded as 961473, what will be the code for SEARCH?

a) 246173

b) 214673

c) 214763

d) 216473

Source PDF page 11.

💡 Hint — try before revealing

Build a consistent letter-to-digit substitution table from the examples.
✅ Answer & explanation

Answer: B — 214673

Reasoning: Substitute S=2,E=1,A=4,R=6,C=7,H=3.

🔁

Related practice: What is the code for ROACH?

✅ Related answer & memory link

Answer: 68473.

Why / remember: R=6,O=8,A=4,C=7,H=3; substituting in ROACH gives 68473.
Confident after revision